请稍等 ...
×

采纳答案成功!

向帮助你的同学说点啥吧!感谢那些助人为乐的人

抛异常,但执行还是OK的,这是什么异常呢

抛出来的异常:D:\Python3.6.5\lib\email\parser.py:50: ResourceWarning: unclosed <socket.socket fd=608, family=AddressFamily.AF_INET, type=SocketKind.SOCK_STREAM, proto=0, laddr=(‘127.0.0.1’, 54007), raddr=(‘127.0.0.1’, 54002)>
feedparser = FeedParser(self._class, policy=self.policy)
D:\Python3.6.5\lib\email\parser.py:50: ResourceWarning: unclosed <socket.socket fd=804, family=AddressFamily.AF_INET, type=SocketKind.SOCK_STREAM, proto=0, laddr=(‘127.0.0.1’, 54288), raddr=(‘127.0.0.1’, 54283)>
feedparser = FeedParser(self._class, policy=self.policy)
.后置条件

代码:
#coding=utf-8
from business.register_business import RegisterBusiness
from selenium import webdriver
#执行case,运行是否成功
import unittest
import warnings
class FirstCase(unittest.TestCase):
def setUp(self):
# warnings.simplefilter(“ignore”, ResourceWarning)
self.driver=webdriver.Chrome()
self.driver.get(“http://www.5itest.cn/register?goto=/”)
self.login=RegisterBusiness(self.driver)

def tearDown(self):
    self.driver.quit()
    print("后置条件")
def test_login_email_error(self):
    email_error=self.login.login_email_error(34,"user11","111111","test1")
    if email_error==True:
        print("注册成功,此条case失败")

def test_login_username_error(self):
    username_error=self.login.login_name_error("111@qq.com","ss","111111","test1")
    if username_error==True:
        print("注册成功,此条case失败")

def test_login_code_error(self):
    code_error = self.login.login_name_error("113@qq.com", "ss", "111111", "test")
    if code_error == True:
        print("注册成功,此条case失败")

def test_login_password_error(self):
    password_error = self.login.login_name_error("112@qq.com", "ss", "111111", "test1")
    if password_error == True:
        print("注册成功,此条case失败")

def test_login_email_success(self):
    sucess = self.login.user_base("114@qq.com", "ss", "111111", "test1")
    if self.login.register_succes()==True:
        print("注册成功")

if name==“main”:
unittest.main()

正在回答 回答被采纳积分+3

1回答

Mushishi 2019-05-11 10:12:20

忽略警告


import warnings
warnings.simplefilter("ignore", ResourceWarning)

0 回复 有任何疑惑可以回复我~
  • 提问者 lkeil #1
    可以忽略这个警告,但为啥会抛出来呢
    回复 有任何疑惑可以回复我~ 2019-05-11 21:14:12
问题已解决,确定采纳
还有疑问,暂不采纳
微信客服

购课补贴
联系客服咨询优惠详情

帮助反馈 APP下载

慕课网APP
您的移动学习伙伴

公众号

扫描二维码
关注慕课网微信公众号